3.1.41 \(\int \frac {1}{x^2 \sqrt {b x^2}} \, dx\) [41]

Optimal. Leaf size=16 \[ -\frac {1}{2 x \sqrt {b x^2}} \]

[Out]

-1/2/x/(b*x^2)^(1/2)

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Rubi [A]
time = 0.00, antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {15, 30} \begin {gather*} -\frac {1}{2 x \sqrt {b x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(x^2*Sqrt[b*x^2]),x]

[Out]

-1/2*1/(x*Sqrt[b*x^2])

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[a^IntPart[m]*((a*x^n)^FracPart[m]/x^(n*FracPart[m])), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {1}{x^2 \sqrt {b x^2}} \, dx &=\frac {x \int \frac {1}{x^3} \, dx}{\sqrt {b x^2}}\\ &=-\frac {1}{2 x \sqrt {b x^2}}\\ \end {align*}

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Mathematica [A]
time = 0.00, size = 15, normalized size = 0.94 \begin {gather*} -\frac {b x}{2 \left (b x^2\right )^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(x^2*Sqrt[b*x^2]),x]

[Out]

-1/2*(b*x)/(b*x^2)^(3/2)

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Maple [A]
time = 0.02, size = 13, normalized size = 0.81

method	result	size
gosper	\(-\frac {1}{2 x \sqrt {b \,x^{2}}}\)	\(13\)
default	\(-\frac {1}{2 x \sqrt {b \,x^{2}}}\)	\(13\)
risch	\(-\frac {1}{2 x \sqrt {b \,x^{2}}}\)	\(13\)
trager	\(\frac {\left (x -1\right ) \left (x +1\right ) \sqrt {b \,x^{2}}}{2 b \,x^{3}}\)	\(22\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^2/(b*x^2)^(1/2),x,method=_RETURNVERBOSE)

[Out]

-1/2/x/(b*x^2)^(1/2)

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Maxima [A]
time = 0.27, size = 8, normalized size = 0.50 \begin {gather*} -\frac {1}{2 \, \sqrt {b} x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^2/(b*x^2)^(1/2),x, algorithm="maxima")

[Out]

-1/2/(sqrt(b)*x^2)

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Fricas [A]
time = 0.36, size = 15, normalized size = 0.94 \begin {gather*} -\frac {\sqrt {b x^{2}}}{2 \, b x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^2/(b*x^2)^(1/2),x, algorithm="fricas")

[Out]

-1/2*sqrt(b*x^2)/(b*x^3)

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Sympy [A]
time = 0.19, size = 14, normalized size = 0.88 \begin {gather*} - \frac {1}{2 x \sqrt {b x^{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**2/(b*x**2)**(1/2),x)

[Out]

-1/(2*x*sqrt(b*x**2))

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Giac [A]
time = 0.87, size = 12, normalized size = 0.75 \begin {gather*} -\frac {1}{2 \, \sqrt {b} x^{2} \mathrm {sgn}\left (x\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^2/(b*x^2)^(1/2),x, algorithm="giac")

[Out]

-1/2/(sqrt(b)*x^2*sgn(x))

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Mupad [B]
time = 0.97, size = 13, normalized size = 0.81 \begin {gather*} -\frac {1}{2\,\sqrt {b}\,x\,\sqrt {x^2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^2*(b*x^2)^(1/2)),x)

[Out]

-1/(2*b^(1/2)*x*(x^2)^(1/2))

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